WebFeb 13, 2009 · Python: date (2015, 3, 31) + relativedelta (months = 6) gives datetime.date (2015, 9, 30). Perl: DateTime->new (year=>2000, month=>3, day=>31)->add (months=>6) gives 2000-10-01T00:00:00. Php: date_create ('2000-03-31', new DateTimeZone ('UTC'))->add (new DateInterval ('P6M')) gives 2000-10-01. Pick your poison. – kmkaplan Feb 10, 2015 at … WebAug 15, 2011 · Using calendar module to find out how many days each month has, you can simply count the months. from calendar import monthrange from datetime import datetime, timedelta def monthdelta (d1, d2): delta = 0 while True: mdays = monthrange (d1.year, d1.month) [1] d1 += timedelta (days=mdays) if d1 <= d2: delta += 1 else: break return delta.
Python datetime.timedelta() function - GeeksforGeeks
WebSep 11, 2024 · Once you have created the instance, you can use its arithmetic functions. You can subtract a day and a month. Take a look at the following code. #instance of datetime date = datetime.datetime(2024,2,1) #subtracting 1 from the month date = date.replace(month=date.month-1) print(date) Output: 2024-01-01 00:00:00 WebThis method converts an argument from a recognized timedelta format / value into a Timedelta type. Parameters arg str, timedelta, list-like or Series. The data to be converted to timedelta. Changed in version 2.0: Strings with units ‘M’, ‘Y’ and ‘y’ do not represent unambiguous timedelta values and will raise an exception. text hoamatland
pandas.to_timedelta — pandas 2.0.0 documentation
Web你可以使用 `datetime` 模块中的 `datetime` 类的以下属性来获取年月日时分秒和毫秒: - year: 年份 - month: 月份 - day: 日期 - hour: 小时 - minute: 分钟 - second: 秒 - microsecond: 微秒 例如: ```python import datetime now = datetime.datetime.now() print(now.year) print(now.month) print(now.day) print(now.hour) print(now.minute) print(now.second) … Webtestdate = date+datetime.timedelta(days=1) if testdate.day == 1: # input date was a last day of month and end of month is favored, so # go to the FIRST of the month AFTER, then go back one day. targetdate.replace(year=targetdate.year+int( (targetmonths+1)/12),month= (targetmonth%12+1),day=1) targetdate+=datetime.timedelta(days=-1) else: Webmy_date_months = my_date + relativedelta ( months = 25) print( my_date_months) # 2026-12-06 14:36:56 The previous output shows a date 25 months later than our input date. Add Years to datetime Object Similar to Example 2, we can apply the relativedelta () function to add years to a datetime object. Consider the Python code below: swr2 playlist heute