Web26 Jun 2024 · using (SQLiteConnection m_dbConnection = new SQLiteConnection (@"Data Source=C:\...\MyDatabase1.sqlite;")) { m_dbConnection.Open (); string sql = "SELECT * FROM highscores WHERE name LIKE ?"; using (SQLiteCommand command = new SQLiteCommand (sql, m_dbConnection)) { command.Parameters.AddWithValue … Web26 Nov 2015 · The standard SQL way of doing what you are saying is INTERSECTION. (SELECT document FROM table WHERE property="id" AND number=43) INTERSECTION (SELECT document FROM table WHERE property="title" AND string="test") You can also do this with self joins if you prefer.
Searching strings in SQLite with SQL LIKE - Esri Community
WebThe SQLite INSTR searches a substring in a string and returns an integer that indicates the position of the substring, which is the first character of the substring. If the substring does … Web22 Nov 2014 · String Search = '1FN3003-4PP00-0AA0' code-Autoit = $sqlString = "SELECT * FROM Table_1 WHERE '1FN3003-4PP00-0AA0' LIKE ProNo% " This code does not work Please Help Me matwachich Universalist Active Members 40 292 posts Posted November 22, 2014 (edited) "SELECT * FROM Table_1 WHERE ProNo LIKE " & _SQLite_Escape ("%" & … larry atkinson nevada
10.1B: Searching a SQLite Database · GitBook
Web10 Jun 2009 · The operand to the right contains the pattern, the left hand operand contains the string to match against the pattern. A percent symbol ("%") in the pattern matches any … Web1 Apr 2024 · I have tried the following AND statement: 1 cursor.execute ("SELECT * FROM `assets2` WHERE `Asset_Serial` AND `Asset_Model` LIKE ?", ('%'+str(SEARCH2.get ())+'%',)) OR statement: 1 cursor.execute ("SELECT * FROM `assets2` WHERE `Asset_Serial` or `Asset_Model` LIKE ?", ('%'+str(SEARCH2.get ())+'%',)) Below is the search2 snippet. 1 2 3 4 … WebSQLite LIKE examples We’ll use the table tracks in the sample database for the demonstration. To find the tracks whose names start with the Wild literal string, you use … larry bailey russellville kentucky